Answer:
The energy of the photon generated in the transition is 3.14*10⁻¹⁹ J
Explanation:
There are two equation that we need to use in order to solve this problem:
The first one is Planck's equation, which describes the relationship between energy and frequency:
E = h*v eq. 1)
Where E is energy, h is Planck's constant (6.626 * 10⁻³⁴ J*s) and v is the radiation frequency.
In order to know the frequency, we use the second equation, which is the wave equation:
c = λ*v eq. 2)
Where c is the speed of light in vacuum (aprx 3 * 10⁸ m/s), and λ is the wavelength. If we solve that equation for v we're left with
v=c/λ eq. 3)
We replace v in eq. 1):
E= c*h/λ
Lastly we put the data we know and solve the equation, keeping in mind the correct use of units (converting 652 nm into m):
[tex]E=\frac{3*10^{8}ms^{-1} *6.626*10^{-34}Js}{633*10^{-9}m }=3.14*10^{-19}J[/tex]
