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A plane flies 464 km east from city A to city B in 50.0 min and then 831 km south from city B to city C in 1.20 h. For the total trip, what are the (a) magnitude and (b) direction of the plane's displacement, the (c) magnitude and (d) direction of its average velocity, and (e) its average speed? Give your angles as positive or negative values of magnitude less than 180 degrees, measured from the +x direction (east).

Respuesta :

Answer:

Explanation:

Displacement = minimum distance between initial and final point

Here displacement = Hypotenuse AC of triangle ABC

= [tex]\sqrt{464^2+831^2}[/tex]

= 951.76 km

Direction of AC

If θ be the angle AC makes with east

Tan θ = 831 / 464 = 1.79

θ = 60.8°

South of east.

c ) average velocity= Displacement / time

Total time =( 50/60 + 1.2 ) hour

2.0333 hour

average velocity = 951.76 km / 2.0333 hour

= 468 km / h

Direction of velocity will be same as the direction of displacement.

e ) speed = distance / time

distance travelled

= 464 + 831 = 1295 km

speed = 1295 / 2.0333

= 636.9 km/ h .

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