Answer:
The power radiated by the hawk is 0.452 Watt.
Explanation:
Given that,
Frequency = 50 Hz
Distance r=60 m
Level = 70 dB
We need to calculate the intensity
Using formula of intensity
[tex]dB=10 log(\dfrac{I}{I_{0}})[/tex]
Put the value into the formula
[tex]70=10 log(\dfrac{I}{10^{-12}})[/tex]
[tex]I=10^{7}\times10^{-12}[/tex]
[tex]I = 1\times10^{-5}\ W/m^2[/tex]
We need to calculate the power radiated by the hawk
Using formula of power
[tex]P = I\times 4\pi r^2[/tex]
Put the value into the formula
[tex]P=1\times10^{-5}\times4\pi\times(60)^2[/tex]
[tex]P=0.452\ W[/tex]
Hence, The power radiated by the hawk is 0.452 Watt.
