Answer:
v = 75 m/s
Explanation:
given data:
mass of gazelle is 25 kg
length of slope is 3 km
height of slope is 40 m
drag force is 20 N
jump height is 2 m
By work energy theorem we have
[tex]\frac{1}{2} mv^2 = F*L + mg(h_1 +h_2)[/tex]
[tex]\frac{1}{2}*25*v^2 = 20*3000 + 25 *9.8(40 + 2)[/tex]
solving for v
[tex]v = \sqrt{\frac{70290}{12.5}}[/tex]
v = 75 m/s