Answer:
1.91 m/s
Explanation:
Speed of boat in still water = [tex]v_{b}[/tex]=1.6 m/s
Speed of the current = [tex]v_c[/tex]=1.05 m/s
Speed of the boat with respect to the shore
Using vector addition we get
[tex]v_{bs}=\sqrt{v_b^2+v_c^2}\\\Rightarrow v_{bs}=\sqrt{1.6^2+1.05^2}\\\Rightarrow v_{bs}=1.91\ m/s[/tex]
Speed of the boat with respect to the shore is 1.91 m/s