contestada

If it takes a ball dropped from rest 2.261 s to fall to the ground, from what height H was it released? Express your answer in meters.

Respuesta :

Answer:

Height, H = 25.04 meters

Explanation:

Initially the ball is at rest, u = 0

Time taken to fall to the ground, t = 2.261 s

Let H is the height from which the ball is released. It can be calculated using the second equation of motion as :

[tex]H=ut+\dfrac{1}{2}at^2[/tex]

Here, a = g

[tex]H=\dfrac{1}{2}gt^2[/tex]            

[tex]H=\dfrac{1}{2}\times 9.8\times (2.261)^2[/tex]

H = 25.04 meters

So, the ball is released form a height of 25.04 meters. Hence, this is the required solution.

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