Answer:
Force, F = −229.72 N
Explanation:
Given that,
First charge particle, [tex]q_1=-6.29\times 10^{-6}\ C[/tex]
Second charged particle, [tex]q_2=5.23\times 10^{-6}\ C[/tex]
Distance between charges, d = 0.0359 m
The electric force between the two charged particles is given by :
[tex]F=k\dfrac{q_1q_2}{d^2}[/tex]
[tex]F=9\times 10^9\times \dfrac{-6.29\times 10^{-6}\times 5.23\times 10^{-6}}{(0.0359)^2}[/tex]
F = −229.72 N
So, the magnitude of force that one particle exerts on the other is 229.72 N. Hence, this is the required solution.
