Answer:
the amount of ferrous sulphate child will digest = 213.3 mg
Step-by-step explanation:
Given,
Amount of FEOSOL Elixir swallowed by child = 1.6 Fluid ounces
= 1.6 x 29.57 ml
= 47.312 ml
[tex]\textrm{Amount of ferrous sulphate contained in 5 ml of of solution}=\ \dfrac{2}{3}\ grams[/tex]
[tex]\textrm{So, amount of ferrous sulphate contained in 1 ml of solution}\ =\ \dfrac{2}{3\times 5}[/tex]
[tex]=\ \dfrac{2}{15}[/tex]
[tex]\textrm{So,the amount of ferrous sulphate contained in the 1.6 ml of FEROSOL}=1.6\times \dfrac{2}{15}[/tex]
[tex]=\ \dfrac{3.2}{15}[/tex]
= 0.2133 gram
= 213.3 mg
So, the amount of ferrous sulphate child will digest = 213.3 mg