Answer:
The greatest height reached by the ball is 0.8 m.
Explanation:
Given that,
Initial velocity = 4 m/s
We need to calculate the greatest height reached by the ball
Using equation of motion
[tex]v^2=u^2+2gh[/tex]
Where, v = final velocity
u = initial velocity
g = acceleration due to gravity
Put the value in the equation
[tex]0=4^2+2\times(-10)\times h[/tex]
[tex]h =\dfrac{16}{20}[/tex]
[tex]h =0.8\ m[/tex]
Hence, The greatest height reached by the ball is 0.8 m.
