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A car enters a freeway with initial velocity of 15.0 m/s and with con stant rate of acceleration, reaches a velocity of 22.5 m/s in a time interval of 3.50 s. a) Determine the value of the car's acceleration. b) Determine the distance traveled by the car in this 3.50 s time interval. c) Determine the average velocity of the car over this 3.50 s time interval.

Respuesta :

carlap12

Answer:

a) The acceleration is 2.14 m/s^{2}

b) The distance traveled by the car is 65.61 m

c) The average velocity is 18.75 m/s

Explanation:

Using the equations that describe an uniformly accelerated motion:

a) [tex]a=\frac{v_f - v_o}{t} =\frac{22.5m/s - 15.0 m/s}{3.50s}[/tex]

b) [tex]d= d_0 + v_0 t + \frac{1}{2} a t^{2} = 0 +15.0 x 3.5 + \frac{2.14x3.50^{2} }{2} = 65.61 m[/tex]

c) [tex]v_m =\frac{d}{t}=\frac{65.61}{3.5}  =18.75 m/s[/tex]

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