Answer:
a) greatest voltage = 29.25 V
b) power = 16 W
Explanation:
The total resistance R of the three resistors in series is:
[tex]R = (6.7 + 30.4 + 16.3) \Omega = 53.4 \Omega[/tex]
a) The greatest current I is the one that will burn the resistor with lower power rating, which is 9.12 W:
[tex]P_{max} = I_{max}^2 R = I_{max}^2 30.4\Omega = 9.12W\\I_{max} = 0.54 A[/tex]
The voltage is:
[tex]V_{max}=IR = 0.54*53.4V= 29.25 V[/tex]
b) When the current is 0.54 A, the power is:
[tex]P = RI^2=53.4*0.3 W = 16W[/tex]
