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What magnitude charge creates a 1.70 N/C electric field at a point 4.60 m away? Express your answer with the appropriate units.

Respuesta :

jorgezarate

Answer:

[tex]Q=4.0*10^{-9}C[/tex]

Explanation:

Electric field of a charge:

[tex]E=k*\frac{Q}{R^{2}}[/tex]

[tex]Q=\frac{E*R^{2}}{K}=1.7*4.6^{2}/(9*10^{9})=4.0*10^{-9}C[/tex]

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