Answer:
[tex]\Delta T = 28.57°C[/tex]
Explanation:
given data:
temperature at outlet of turbine = 260°C
Flow rate = 2 kg/min = 0.033 kg/s
output power = 1 kW
specific heat = 1.05 kJ/kg.K
We know that power generated by turbine is equal to change in enthalpy
[tex]W = h_2 - h_1[/tex]
[tex]= mCp(\Delta T)[/tex]
[tex]1*10^3 = 0.0333*1.05*10^3 * \Delta T[/tex]
[tex]\Delta T = \frac{10^3}{0.033*1.05*10^3}[/tex]
[tex]\Delta T = 28.57°C[/tex]