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An airplane over the Pacific sights an atoll at 20 degree angle of depression. If the plane is 425 m above water, how many kilometers is it from a point 425 m above the center of the atoll?

Respuesta :

Answer:

[tex]1.167 km[/tex]

Step-by-step explanation:

We are given with-

Height of airplane from water [tex]a[/tex] = [tex]425 m[/tex]

Angle of depression (∅)= 20°

Now,

[tex]tan(20) = \frac{b}{a}[/tex]

[tex]a = \frac{b}{tan(20)} \\a = \frac{425}{tan(20} \\a = 1167.677 m[/tex]

[tex]a = 1.167 km[/tex]

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