Answer:
[tex]\sin x + \sqrt{1-\sin^2x}[/tex]
Step-by-step explanation:
Given: sin x + cos x
To change the given trigonometry expression in term of sine only.
Trigonometry identity:-
- [tex]\sin^2x+\cos^2x=1[/tex]
- [tex]\cos x=\sqrt{1-\sin^2x}[/tex]
Expression: [tex]\sin x+\cos x[/tex]
We get rid of cos x from expression and write as sine form.
Expression: [tex]\sin x + \sqrt{1-\sin^2x}[/tex] [tex]\because \cos x=\sqrt{1-\sin^2x}[/tex]
Hence, The final expression is only sine function.
