Answer:
[tex]T_4[/tex]= 506.79 K
Explanation:
Given that
Minimum temperature [tex]T_1[/tex]= 25 C
Pressure = 100 KPa
Highest temperature [tex]T_3[/tex]= 1000 C
Compression ratio r= 10
We know that for ideal Otto cycle
[tex]\dfrac{T_3}{T_4}=r^{\gamma -1}[/tex]
Where [tex]T_3[/tex] is the exhaust temperature.
Now by putting the values
[tex]\dfrac{T_3}{T_4}=r^{\gamma -1}[/tex]
[tex]\dfrac{1000+273}{T_4}=10^{1.4-1}[/tex]
[tex]T_4[/tex]= 506.79 K