Answer:
The weight is 4.492 lb
The density is [tex]0.5614 lbm/ft^{3}[/tex]
Solution:
As per the question:
Volume of spacecraft component, [tex]V_{s} = 8ft^{3}[/tex]
Mass of the component of spacecraft, [tex]m_{s} = 25 lb[/tex]
Acceleration of gravity at a point on Earth, [tex]g_{E} = 31.0 ft/s^{2}[/tex]
Acceleration of gravity on Moon, [tex]g_{M} = 5.57 ft/s^{2}[/tex]
Now,
The weight of the component, [tex]w_{c} = m_{c}\times \frac{g_{M}}{g_{E}}[/tex]
[tex]w_{c} = 25\times \frac{5.57}{31.0}[/tex]
[tex]w_{c} = 4.492 lb[/tex]
Now,
Average density, [tex]\rho_{avg}[/tex]
[tex]\rho_{avg} = \farc{w_{s}}{V_{s}}[/tex]
[tex]\rho_{avg} = \farc{4.492}{8} = 0.5614 lbm/ft^{3}[/tex]
Answer:
density=3.125pounds/ft^3
weight=4.35lbf
Explanation:
Density is a property of matter that indicates how much mass a body has in a given volume.
It is given by the following equation.
ρ=m/v (1)
where
ρ=density
m=mass
v=volume
The weight on the other hand is the force which the earth (or the moon) attracts to a body with mass, this force is given by the following equation
W=mg (2)
W=weight
m=mass
g=gravity
to solve this problem we have to calculate the mass of the component using the ecuation number 2
W=mg
m=w/g
w=25lbf=804.35pound .ft/s^2
g=32.2ft/s^2
m=804.35/32.2=25 pounds
density
ρ=m/v (1)
ρ=25pounds/8ft^3
ρ=3.125pounds/ft^3 =density
weight in the moon
W=mg
W=(25pounds)(5.57ft/s^2.)=139.25pound .ft/s^2=4.35lbf
