Respuesta :

alejandraarnedo1542

Answer:

[tex](\rho*Q)/(\mu*h)[/tex]

Explanation:

First, we need to establish the unit of each variable:  

  • [tex]Q (flow rate)=[m^3/s][/tex]
  • [tex]\rho(density)=[kg/m^3][/tex]
  • [tex]h(depth)=[m][/tex]
  • [tex]\mu( viscosity )=[kg/m*s][/tex]

To eliminate [tex]m^3[/tex] we need to multiply Q by [tex]\rho[/tex]. Then to eliminate kg we divide [tex]\rho[/tex] by [tex]\mu[/tex]. Finally, multiply [tex]\mu[/tex] by h we can let the constant dimensionless.

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