Answer:
minimum flow rate provided by pump is 0.02513 m^3/s
Explanation:
Given data:
Exit velocity of nozzle = 20m/s
Exit diameter = 40 mm
We know that flow rate Q is given as
[tex]Q = A \times V[/tex]
where A is Area
[tex]A =\frac{\pi}{4} \times (40\times 10^{-3})^2 = 1.256\times 10^{-3} m^2[/tex]
[tex]Q = 1.256\times 10^{-3} \times 20 = 0.02513 m^3/s[/tex]
minimum flow rate provided by pump is 0.02513 m^3/s
