Answer:
12024000 lb*ft
Explanation:
The total work will be the sum of the energy consumed by friction plus the kinetic energy the car attained.
L = Ek + Lf
Lf = Ff * d
Ek = 1/2 * m * v^2
Therefore:
L = Ff * d + 1/2 * m * v^2
L = 80 * 300 + 1/2 * 15000 * 40^2 = 12024000 lb*ft
THe total work done on the car is of 12024000 lb*ft