Answer:
[tex]t_2 = 14.4 min[/tex]
Explanation:
Given data:
Number of frame is 12+ 8 = 20
Total filtrate is 360 lb
we know
For 1 plate area [tex]= \frac{65}{12} ft^2[/tex]
Then for 20 are PLATE [tex]= 20\tmes \frac{65}{12} ft^2 = 108.33 ft^2[/tex]
filtrate equation is given as
[tex]t\frac{\mu_s\times(\alpha v) V^2}{A^2(-\Delta P)}[/tex]
In the above equation only t and A is variable , all other terms are constant
Therefore we have
[tex]\frac{t_2}{t_1}= \frac{A_1}{A_2} = [\frac{65}{105.33}]^2 = 0.36[/tex]
[tex]t_2 = 0.36\times 40 = 14.4 min[/tex]
[tex]t_2 = 14.4 min[/tex]
