Answer:
Vinegar has 4.09% of acetic acid.
Explanation:
The neutralization reaction is:
[tex]CH_{3}COOH + KOH=>CH_{3}COOK + H_{2}O[/tex]
Each mol of KOH reacts with each mole of acetic acid so the quantity of moles of acetic acid is:
[tex]M= 0.46 \frac{mol}{l}*37ml*\frac{1l}{1000ml} =0.01702 mol[/tex]
The mass of acetic acid is:
0.01702 mol×60.02g/mol=1.0215 g Acetic Acid
Finally, the percentage is:
%=1.0215 g Acetic Acid÷25g vinegar(solution)=4.09%
