Answer:
[tex]\boxed{2.23 \times 10^{7}{\text{ MJ}}}[/tex]
Explanation:
42.7 MJ/kg =42 700 MJ/t
1. Energy from PP
[tex]\text{Energy from PP} = \text{1200 t PP} \times \dfrac{\text{42 700 MJ}}{\text{1 t PP}} = 5.12 \times 10^{7}\text{ MJ}[/tex]
2. Useful energy
[tex]\text{Useful energy} = 5.12 \times 10^{7}\text{ MJ supplied } \times \dfrac{\text{ 24 MJ useful}}{\text{100 MJ supplied}} = 2.23 \times 10^{7}\text{ MJ useful}\\\\\text{The power plant supplies $\boxed{\mathbf{2.23 \times 10^{7}{\text{ MJ}}}}$ of useful energy}[/tex]
