Answer : The de Broglie wavelength will be [tex]3.68\times 10^{-33}m[/tex]
Solution :
The formula used for de Broglie wavelength is:
[tex]\lambda=\frac{h}{mv}[/tex] ..........(1)
where,
[tex]\lambda[/tex] = wavelength = ?
h = Planck's constant = [tex]6.626\times 10^{-34}Js[/tex]
m = mass = 1.2 g = 0.0012 kg
Conversion used : 1 kg = 1000 g
v = velocity = 150 m/s
Now put all the given values in equation 1, we get:
[tex]\lambda=\frac{6.626\times 10^{-34}Js}{(0.0012kg)\times (150m/s)}[/tex]
[tex]\lambda=3.68\times 10^{-33}m[/tex]
Therefore, the de Broglie wavelength will be [tex]3.68\times 10^{-33}m[/tex]
