Answer:
The equivalent capacitance will be [tex]15\mu F[/tex]
Explanation:
We have given two capacitance [tex]C_=10\mu F\ and\ C_2=20\mu F[/tex]
They are connected in parallel
So equivalent capacitance [tex]C=C_1+C_2=10+20=30\mu F[/tex]
This equivalent capacitance is now connected in series with [tex]30\mu F[/tex]
In series combination of capacitors the equivalent capacitance is given by [tex]\frac{1}{C}=\frac{1}{30}+\frac{1}{30}[/tex]
[tex]C=\frac{30}{2}=15\mu F[/tex]
So the equivalent capacitance will be [tex]15\mu F[/tex]
