Answer:
The distance is 2 cm
Solution:
According to the question:
Magnetic field of Earth, B_{E} = [tex]5.0\times 10^{- 5} T[/tex]
Current, I = 5.0 A
We know that the formula of magnetic field is given by:
[tex]B = \farc{\mu_{o}I}{2\pi d}[/tex]
where
d = distance from current carrying wire
Now,
[tex]d = \frac{\mu_{o}I}{2\pi B}[/tex]
[tex]d = \frac{4\pi\times 10^{- 7}\times 5.0}{2\pi\times 5.0\times 10^{- 5}}[/tex]
d = 0.02 m 2 cm
