Respuesta :
Answer :
(a) The volume of ethanol liquid needed are, 2.4 L
(b) The volume of ethanol liquid needed are, 1.9 L
(c) The volume of ethanol liquid needed are, 1.6 L
(d) The volume of ethanol liquid needed are, 1.7 L
Explanation : Given,
Volume of solution = 250 mL = 0.250 L (1 l = 1000 mL)
Concentration of solution = 350 mM = 0.350 M (1 mM = 0.001 M)
First we have to calculate the moles of solution.
[tex]\text{Moles of solution}=\text{Concentration of solution}\times \text{Volume of solution}=0.350M\times 0.250L=0.0875mole[/tex]
(a) For ethanol liquid :
To we have to calculate the mass of ethanol.
[tex]\text{Mass of ethanol}=\frac{\text{Moles}}{\text{Molar mass of ethanol}}=\frac{0.0875mole}{46g/mole}=0.0019g[/tex]
Now we have to calculate the volume of ethanol.
[tex]Volume=\frac{Mass}{Density}=\frac{0.0019g}{0.789g/cm^3}=0.0024cm^3=0.0024mL=2.4L[/tex]
(b) For acetone liquid :
To we have to calculate the mass of acetone.
[tex]\text{Mass of acetone}=\frac{\text{Moles}}{\text{Molar mass of acetone}}=\frac{0.0875mole}{58g/mole}=0.0015g[/tex]
Now we have to calculate the volume of acetone.
[tex]Volume=\frac{Mass}{Density}=\frac{0.0015g}{0.791g/cm^3}=0.0019cm^3=0.0019mL=1.9L[/tex]
(c) For formic acid liquid :
To we have to calculate the mass of formic acid.
[tex]\text{Mass of formic acid}=\frac{\text{Moles}}{\text{Molar mass of formic acid}}=\frac{0.0875mole}{46g/mole}=0.0019g[/tex]
Now we have to calculate the volume of formic acid.
[tex]Volume=\frac{Mass}{Density}=\frac{0.0019g}{1.220g/cm^3}=0.0016cm^3=0.0016mL=1.6L[/tex]
(d) For tert-Butylamine liquid :
To we have to calculate the mass of tert-Butylamine.
[tex]\text{Mass of tert-Butylamine}=\frac{\text{Moles}}{\text{Molar mass of tert-Butylamine}}=\frac{0.0875mole}{73g/mole}=0.0012g[/tex]
Now we have to calculate the volume of tert-Butylamine.
[tex]Volume=\frac{Mass}{Density}=\frac{0.0012g}{0.696g/cm^3}=0.0017cm^3=0.0017mL=1.7L[/tex]
