Answer:
Maximum height of the arrow is 203 feets
Step-by-step explanation:
It is given that,
The height of the arrow as a function of time t is given by :
[tex]h(t)=-16t^2+64t+11[/tex]..........(1)
t is in seconds
We need to find the maximum height of the arrow. For maximum height differentiating equation (1) wrt t as :
[tex]\dfrac{dh(t)}{dt}=0[/tex]
[tex]\dfrac{d(-16t^2+64t+11)}{dt}=0[/tex]
[tex]-32t+64=0[/tex]
t = 2 seconds
Put the value of t in equation (1) as :
[tex]h(t)=-16(2)^2+64(2)+11[/tex]
h(t) = 203 feet
So, the maximum height reached by the arrow is 203 feet. Hence, this is the required solution.
