Zene decides to canoe 7 miles upstream on a river to a waterfall and then canoe back. The total trip (excluding the time spent at the waterfall) takes 8 hours. Zene knows she can canoe at an average speed of 3 miles per hour in still water. What is the speed of the current?

Respuesta :

Answer:

V = 1.94 mi/h

Step-by-step explanation:

You can asume that the current helps her when she is downstream and hinders her when she is upstream.

downstream:

[tex]v_T = v + 3[/tex]

upstream:

[tex]v_T=3 - v[/tex]

If v = x / t, then t = x / v thus the time she took to do each part was:

downstream:

[tex]t_d=\frac{7}{3+v}[/tex]

upstream:

[tex]t_u=\frac{7}{3-v}[/tex]

The total time is [tex]t_u+t_d=8[/tex]

Therefore:

[tex]\frac{7}{3-v}+\frac{7}{3+v}=8[/tex]

[tex](7)(3-v)+(7)(3+v)=8(3-v)(3+v)[/tex]

[tex](7)(3-v+3+v)=8(9-v^2)[/tex]

[tex](7)(6)=72-8v^2[/tex]

[tex]42-72=-8v^2[/tex]

[tex]v^2=30/8[/tex]

[tex]v=\sqrt{\frac{30}{8} }[/tex]

v≈1,94

Answer:

V = 1.94 mi/h

Step-by-step explanation:

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