A basketball​ player's hang time is the time spent in the air when shooting a basket. The formula t=d [tex]\sqrt{x}[/tex]d/2 Models hang​ time, t, in​ seconds, in terms of the vertical distance of a​ player's jump,​ d, in feet. When a particular player dunked a​ basketball, his hang time for the shot was approximately 1.28 seconds. What was the vertical​ distance, d, of his​ jump, rounded to the nearest​ tenth?

Answer: 6.5 feet
1.27=[tex]\sqrt{d} /2[/tex]
(2X1.27)^{2}=d
d=2.54^{2}
d=6.4516 feet (Round)
d=6.5 feet