Answer:
Explanation:
Given parameters:
Mass of calcium carbonate = 1.73g
Mass of sodium carbonate = 2.34g
Mass of magnesium sulfate = 1.93g
Unknown:
Percentage of calcium carbonate in the mixture
Solution:
The mixture consists of :
calcium carbonate + sodium carbonate + magnesium sulfate:
To find the percentage of calcium carbonate, we must first find the mass of the mixture by summing the masses of the different compounds that makes up the mixture:
Mass of the mixture = 1.73 + 2.34 + 1.93 = 6.00g
Therefore,
percentage of calcium carbonate = [tex]\frac{mass of calcium carbonate}{mass of mixture}[/tex] x 100
Percentage of calcium carbonate = [tex]\frac{1.73}{6}[/tex] x 100 = 28.83%
28.83 % of calcium carbonate is present.
Calcium carbonate [tex]\rm (CaCO_{3})[/tex] is the compound found in aragonite and calcite and is the major element of shells and skeletons. It is also used as a dietary supplement.
Given,
The total mass of the mixture will be:
[tex]\begin{aligned}\rm Mass \;of \;mixture} &= \rm \;mass\; of \;CaCO_{3} + \rm \;mass \;of \;NaCO_{3} + \rm \;mass \;of\; MgSO_{4}\\\\&= 1.73 \rm \;g + 2.34 \rm \;g + 1.93 \rm \;g \\\\&= 6.00 \rm \;g \end{aligned}[/tex]
The percentage of a compound or an element in a mixture can be calculated as:
[tex]\% \text{of substance} = (\dfrac{\text{mass of substance} }{\text{mass of mixture}}) \times 100[/tex]
Now substitute values in the formula:
[tex]\begin{aligned}\% \text{of substance} &= (\dfrac{\text{1.73 g} }{\text{6.00 g}}) \times 100\\\\&= 28.8 \%\end{aligned}[/tex]
Therefore, 28.83 % of calcium carbonate is present.
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