Answer:
the evaluation in SI unit will be [tex]2.69\times 10^{-5}sec^{2}[/tex]
Explanation:
We have evaluate [tex]\frac{(204mm\times 0.00457kg)}{34.6N}[/tex]
We know that 1 mm [tex]=10^{-3}m[/tex]
So 240 mm [tex]=204\times 10^{-3}m[/tex]
Newton can be written as [tex]kgm/sec^2[/tex]
So [tex]\frac{(204\times 10^{-3}m)\times 0.00457kg}{34.6kgm/sec^2}=2.69\times 10^{-5}sec^{2}[/tex]
So the evaluation in SI unit will be [tex]2.69\times 10^{-5}sec^{2}[/tex]
