Answer:
[tex](a)\ 10^4\ mg/L[/tex]
[tex](b)\ 10^{10}\ mg/L[/tex]
Explanation:
(a) As given in question,
concentration of zinc in atmosphere = 10 g/L
By converting g to mg,
1 g = 1000 mg
=> 10 g = 10 x 1000 mg
[tex]=\ 10^4\ mg[/tex]
Hence, the concentration of zinc in the environment in mg/L is [tex]10^4\ mg/L.[/tex]
(a) As given in question,
concentration of zinc in atmosphere = 10 g/L
By converting g to nano gm,
[tex]1\ g\ =\ 10^9\ nano\ gm[/tex]
[tex]=>\ 10\ g\ =\ 10\ \times\ 10^9\ nano\ gm[/tex]
[tex]=\ 10^{10}\ nano\ gm[/tex]
Hence, the concentration of zinc in the environment in nano gm/L is [tex]10^{10}\ nano\ gm/L.[/tex]
