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Find the measure of x. Line PU has points R and S between points P and U, lines QR and ST are parallel, line QR intersects line PU at point R, line ST intersects line PU at point S, the measure of angle PRQ is 135 degrees, and the measure of angle UST is 15 ( x plus 2 ) degrees. X = −1 x = 7 x = 9 x = 13

Respuesta :

Ashraf82

Answer:

The value of x is 1

Step-by-step explanation:

* Lets explain how to solve the problem

- Line PU has points R and S between points P and U

- Line QR intersects line PU at point R

- Line ST intersects line PU at point S

- Lines QR and ST are parallel

- Look to the attached figure

∵ QR // ST

∴ m∠TSU = m∠QRU ⇒ corresponding angles

∵ m∠TSU = 15(x + 2)°

∴ m∠QRU = 15(x + 2)

∵ Points P, R, S lie on the same line

∵ RQ intersects PS at R

∵ m∠PRQ + m∠QRU = 180° ⇒ straight angle

∵ m∠PRQ = 135°

∵ m∠QRU = 15(x + 2)°

∴ 135 + 15(x + 2) = 180

∴ 135 + 15x + 30 = 180

- Add like terms

∴ 15x + 165 = 180

- Subtract 165 from both sides

∴ 15x = 15

- Divide both sides by 15

∴ x = 1

∴ The value of x is 1

Ver imagen Ashraf82
asalmon12

The value of x is 1

Step-by-step explanation:

* Lets explain how to solve the problem

- Line PU has points R and S between points P and U

- Line QR intersects line PU at point R

- Line ST intersects line PU at point S

- Lines QR and ST are parallel

- Look to the attached figure

∵ QR // ST

∴ m∠TSU = m∠QRU ⇒ corresponding angles

∵ m∠TSU = 15(x + 2)°

∴ m∠QRU = 15(x + 2)

∵ Points P, R, S lie on the same line

∵ RQ intersects PS at R

∵ m∠PRQ + m∠QRU = 180° ⇒ straight angle

∵ m∠PRQ = 135°

∵ m∠QRU = 15(x + 2)°

∴ 135 + 15(x + 2) = 180

∴ 135 + 15x + 30 = 180

- Add like terms

∴ 15x + 165 = 180

- Subtract 165 from both sides

∴ 15x = 15

- Divide both sides by 15

∴ x = 1

∴ The value of x is 1

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