Respuesta :

The perimeter of a rectangle is given by

[tex]P = 2(w+l)[/tex]

If the length is 2 more than the width, we have

[tex]l = w+2[/tex]

So, the perimeter becomes

[tex]P = 2(w+(w+2)) = 2(2w+2) = 4w+4[/tex]

If the perimeter is 40, we have

[tex]40 = 4w+4 \iff 4w=36 \iff w=9[/tex]

So, the length is

[tex]l = w+2 = 9+2 = 11[/tex]

varshamittal029

Length is 11 feet & width is 9 feet.

What is the formula of perimeter of rectangle ?

If length of a rectangle be L & width be W.

Then, perimeter of rectangle = 2×(L+W)

What are the required length & width ?

Given, Length of the rectangle is 2 feet more than its width.

Let, width of rectangle = x feet

Then length of the rectangle = (x+2) feet

Given, perimeter is 40 feet.

According to the question,

2×{(x+2)+x} = 40

⇒ {x+2+x} = 40/2

⇒ 2x+2 = 20

⇒ 2x = 20-2

⇒ 2x = 18

⇒ x = 18/2 = 9

So, width = 9 feet

Therefore, length = 9+2 = 11 feet

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https://brainly.com/question/3749071

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