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Write the equation of a function whose parent function, f(x) = x + 5, is shifted 3 units to the right.

a) g(x) = x + 3
b) g(x) = x + 8
c) g(x) = x − 8
d_ g(x) = x + 2

Respuesta :

IbanBeast
B because it’s 3 units shifted right which makes 5 turn into 8

Answer:

[tex]g(x) = x + 2[/tex]

Step-by-step explanation:

Parent function [tex]f(x) = x + 5[/tex], is shifted 3 units to the right.

If f(x) is shifted 'a' units to the right then f(x) becomes f(x-a)

If f(x) is shifted 'a' units to the left then f(x) becomes f(x+a)

[tex]f(x) = x + 5[/tex], is shifted 3 units to the right.

Then we subtract 3 from x

So , [tex]f(x) = x + 5[/tex] becomes [tex]f(x-3) = x-3 + 5=x+2[/tex]

[tex]g(x) = x + 2[/tex]

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