Answer:
Take 5 ml of dye and add 3 ml of water
Thus,
The total volume of solution becomes = 8 mL
now,
This solution of 8 mL contains [tex]\frac{\textup{5}}{\textup{8}}[/tex] part of dye and [tex]\frac{\textup{3}}{\textup{8}}[/tex] part of water.
Next step is to take out 2 mL of solution
thus,
Volume of dye in 2 mL solution = [tex]\frac{\textup{5}}{\textup{8}}\times2\ mL[/tex]
or
Volume of dye in 2 mL solution = 1.25 mL
hence,
the 1.25 mL dye is measured.
Step-by-step explanation:
Given:
10-mL graduate calibrated in 1-mL units
dye solution to be measured = 1.25 mL
Now,
take 5 ml of dye and add 3 ml of water
Thus,
The total volume of solution becomes = 8 mL
now,
This solution of 8 mL contains [tex]\frac{\textup{5}}{\textup{8}}[/tex] part of dye and [tex]\frac{\textup{3}}{\textup{8}}[/tex] part of water.
Next step is to take out 2 mL of solution
thus,
Volume of dye in 2 mL solution = [tex]\frac{\textup{5}}{\textup{8}}\times2\ mL[/tex]
or
Volume of dye in 2 mL solution = 1.25 mL
hence,
the 1.25 mL dye is measured.