Answer: [tex]6.25\%[/tex]
Step-by-step explanation:
Given: A pharmacist attempts to weigh 0.375 g of morphine sulfate on a balance of dubious accuracy. When checked on a highly accurate balance, the weight is found to be 0.400 g.
i.e. Estimated weight = 0.375 g and Actual weight = 0.400 g
Now, the percentage of error in the first weighing is given by :-
[tex]\%\text{ Error}=\dfrac{|\text{Estimate-Actual}|}{\text{Actual}}\times100\\\\=\dfrac{|0.375-0.400|}{0.400}\times100\\\\=\dfrac{|-0.025|}{0.400}\times100\\\\=\dfrac{0.025}{0.4}\times100\\\\=\dfrac{25\times10}{4\times1000}\times100=\dfrac{25}{4}=6.25\%[/tex]
Hence, the percentage of error in the first weighing = [tex]6.25\%[/tex]
