Answer:
Kay's husband drove at a speed of 50 mph
Step-by-step explanation:
This is a problem of simple motion.
First of all we must calculate how far Kay traveled to her job, and then estimate the speed with which her husband traveled later.
d=vt
v=45 mph
t= 20 minutes/60 min/hour = 0.333 h (to be consistent with the units)
d= 45mph*0.333h= 15 miles
If Kay took 20 minutes to get to work and her husband left home two minutes after her and they both arrived at the same time, it means he took 18 minutes to travel the same distance.
To calculate the speed with which Kate's husband made the tour, we will use the same initial formula and isolate the value of "V"
d=vt; so
v=[tex]\frac{d}{t}[/tex]
d= 15 miles
t= 18 minutes/60 min/hour = 0.30 h (to be consistent with the units)
v=[tex]\frac{d}{t}=\frac{15 miles}{0.3 h}=50mph[/tex]
Kay's husband drove at a speed of 50 mph
