Answer:
35.7 kg lid we put
Explanation:
given data
temperature = 105 celcius
diameter = 15 cm
Patm = 101 kPa
to find out
How heavy a lid should you put
solution
we know Psaturated from table for temperature is 105 celcius is
Psat = 120.8 kPa
so
area will be here
area = [tex]\frac{\pi }{4} d^2[/tex] ..................1
here d is diameter
put the value in equation 1
area = [tex]\frac{\pi }{4} 0.15^2[/tex]
area = 0.01767 m²
so net force is
Fnet = ( Psat - Patm ) × area
Fnet = ( 120.8 - 101 ) × 0.01767
Fnet = 0.3498 KN = 350 N
we know
Fnet = mg
mass = [tex]\frac{Fnet}{g}[/tex]
mass = [tex]\frac{350}{9.8}[/tex]
mass = 35.7 kg
so 35.7 kg lid we put
