1) A 25 μL diluted sample (1:25) of protein was added to 2 ml of Bradford reaction assay tube. The absorbance at 595 was 0.75 and according to a BSA standard curve corresponding to 0.025 mg protein on the x-axis. What is the protein concentration (mg/ml) of the original protein?

Respuesta :

Answer:

   protein concentration  [tex]= 2.5\times 10^{-5} mg/ml[/tex]

Explanation:

from the given information

total amount of protein is 0.025 mg

amount of dilute solution is [tex]25\mu L[/tex]

Therefore original concentration is given as

original concentration [tex]=\frac{0.025 mg}{25 \mu L} = 0.001 mg/\mu L[/tex]

                                      [tex]= 0.001 mg/\mu L \times 25[/tex]

HERE 25 is dilution factor

                                      [tex]= 0.025 mg/\mu L[/tex]

convert [tex]mg/\mu L\  to\ mg/ml = 0.025 mg/\mu\ L \times \frac{1}{10^3 \mu\  L}[/tex]

                                              [tex]= 2.5\times 10^{-5} mg/ml[/tex]