Answer:
723.54 N
Explanation:
Weight of anchor = 833 N
density of iron = 7800 mg/m^3
density of sea water = 1025 kg/m^3
According to the Archimedes principle, if a body is immersed wholly or partly in a liquid it experiences a loss in weight of the body which is equal to the weight of liquid displaced by the body.
The loss in the weight of body is equal to the buoyant force acting on the body.
The formula for the buoyant force acting on the body
= volume of body x density of liquid x acceleration due to gravity
Weight of anchor = mass x acceleration due to gravity
833 = m x 9.8
m = 85 kg
mass of anchor = Volume of anchor x density of iron
85 = V x 7800
V = 0.01089 m^3
Buoyant force on the anchor = Volume of anchor x density of sea water x g
= 0.01089 x 1025 x 9.8 = 109.46 N
So, the tension in the chain = Apparent weight of the anchor
= Weight - Buoyant force
= 833 - 109.46 = 723.54 N
Thus, the tension in the chain is 723.54 N.
