Answer:
Density, [tex]\rho = 1.3937 kg/m^{3}[/tex]
Specific volume, [tex]V_{s} = 0.717 m^{3}/kg[/tex]
Given:
Air Pressure, [tex]P_{a} = 1.2 atm[/tex]
Temperature, T = 300 K
Solution:
Now, from the eqn:
[tex]P_{a}V = mRT[/tex]
[tex]P_{a} = \frac{m}{V}RT = \rho RT[/tex]
where
[tex]\rho = density[/tex]
[tex]\rho = \frac{1.2\times 10^{5}}{0.287\times 300} = 1.3937 kg/m^{3}[/tex]
Now, for specific volume:
[tex]V_{s} = \frac{1}{density, \rho}[/tex]
[tex]V_{s} = \frac{1}{1.3937} = 0.717 m^{3}/kg[/tex]
