Given : Sample size : n= 16
Degree of freedom = n-1=15
The obtained t-statistic value = 1.94
Since, The treatment is expected to increase scores and the sample mean shows an increase.
Let [tex]\mu_0[/tex] be the population mean before and [tex]\mu[/tex] denotes the population mean after the treatment.
then the related hypothesis will be :-
[tex]\text{Null hypothesis }H_0:\mu_0=\mu\\\\\text{Alternative hypothesis } H_1:\mu_0<\mu[/tex]
Since the alternative hypothesis is left-tailed, so the test is a left tailed test.
The critical value for [tex]\alpha=0.05[/tex]=1.753
Since, the obtained value (1.94) is greater than the critical value (1.753) so we reject the null hypothesis .
Therefore, we have enough evidence to support the alternative hypothesis.
Hence, we conclude that treatment may successful to increase scores and the sample mean shows an increase.
