Respuesta :
Answer:
[tex]Q = \frac{0.068}{E}[/tex]
where E = electric field intensity
Explanation:
As we know that plastic ball is suspended by a string which makes 30 degree angle with the vertical
So here force due to electrostatic force on the charged ball is in horizontal direction along the direction of electric field
while weight of the ball is vertically downwards
so here we have
[tex]QE = F_x[/tex]
[tex]mg = F_y[/tex]
since string makes 30 degree angle with the vertical so we will have
[tex]tan\theta = \frac{F_x}{F_y}[/tex]
[tex]tan30 = \frac{QE}{mg}[/tex]
[tex]Q = \frac{mg}{E}tan30[/tex]
[tex]Q = \frac{0.012\times 9.81}{E} tan30[/tex]
[tex]Q = \frac{0.068}{E}[/tex]
where E = electric field intensity
The net charge on the small plastic ball which is suspended by a string in a uniform is 0.068/E C.
What is electric field?
The electric field is the field, which is surrounded by the electric charged. The electric field is the electric force per unit charge.
A point charge on a string in equilibrium with an electric field can be given as,
[tex]E=\dfrac{mg \tan\theta}{Q}[/tex]
Here, (m) is the mass, (g) is acceleration due to gravity, and (Q) is the charge.
A small 12.00 g plastic ball is suspended by a string in a uniform, horizontal electric field.
The ball is in equilibrium when the string makes a 30 degrees angle with the vertical. Thus, by the above formula,
[tex]E=\dfrac{(0.012)(9.81)\tan(30)}{Q}\\Q=\dfrac{0.068}{E}\rm\; C[/tex]
Thus, the net charge on the small plastic ball which is suspended by a string in a uniform is 0.068/E C.
Learn more about electric field here;
https://brainly.com/question/14372859
