Respuesta :
Answer:
Part a)
[tex]\delta y = 0.85 m[/tex]
Part b)
[tex]\theta = 0.65 degree[/tex]
Explanation:
Part a)
As we know that the target is at distance 75 m from the hunter position
so here we will have
[tex]x = v_x t[/tex]
here we know that
[tex]v_x = 180 m/s[/tex]
so we have
[tex]75.0 = 180 (t)[/tex]
[tex]t = 0.42 s[/tex]
now in the same time bullet will go vertically downwards by distance
[tex]\delta y = \frac{1}{2}gt^2[/tex]
[tex]\delta y = \frac{1}{2}(9.81)(0.42^2)[/tex]
[tex]\delta y = 0.85 m[/tex]
Part b)
In order to hit the target at same level we need to shot at such angle that the range will be 75 m
so here we have
[tex]R = \frac{v^2 sin(2\theta)}{g}[/tex]
[tex]75 = \frac{180^2 sin(2\theta)}{9.81}[/tex]
[tex]\theta = 0.65 degree[/tex]
