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One line passes through the points (-6,0) and (-4,6) another line passes through the points (5,-2) and (8,7)

Is it parallel , perpendicular , or neither

Respuesta :

BasketballEinstein

Answer:

Parallel

Step-by-step explanation:

-y₁ + y₂\-x₁ + x₂ = m

[tex] \frac{2 + 7}{ -5 + 8} = \frac{9}{3} = 3[/tex]

[tex] \frac{0 + 6}{6 - 4} = \frac{6}{2} = 3[/tex]

Both rate of changes [slopes] result in three, therefore both lines are parallel.

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MrRoyal

Lines can be parallel, perpendicular or neither

Both lines are neither perpendicular nor parallel

The first line passes through (-6,0) and (-4,6)

The slope (m1) of the first line is:

[tex]m_1 = \frac{y_2 - y_1}{x_2 - x_1}[/tex]

So, we have:

[tex]m_1 = \frac{6-0}{-4--6}[/tex]

[tex]m_1 = \frac{6}{2}[/tex]

[tex]m_1 = 3[/tex]

The second line passes through (5,-2) and (8,7)

The slope (m2) of the second line is:

[tex]m_2 = \frac{y_2 - y_1}{x_2 - x_1}[/tex]

So, we have:

[tex]m_2 = \frac{7--2}{8-5}[/tex]

[tex]m_2 = \frac{5}{3}[/tex]

  • If [tex]m_1 = m_2[/tex], then the lines are parallel
  • If [tex]m_1 = -\frac{1}m_2[/tex], then the lines are perpendicular

None of the above conditions is true.

Hence, the lines are neither perpendicular nor parallel

Read more about perpendicular and parallel lines at:

https://brainly.com/question/12731518

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