Answer:
2.1 s
Explanation:
The motion of the ball is a projectile motion. We know that the horizontal range of the ball is
[tex]d = 50 m[/tex]
And that the initial speed of the ball is
[tex]u=25 m/s[/tex]
at an angle of
[tex]\theta=20^{\circ}[/tex]
So, the horizontal speed of the ball (which is constant during the entire motion) is
[tex]u_x = u cos \theta = 25 \cdot cos 20^{\circ} = 23.5 m/s[/tex]
And since the horizontal range is 50 m, the time taken for the ball to cover this distance was
[tex]t=\frac{d}{u_x}=\frac{50}{23.5}=2.1 s[/tex]
which is the time the ball spent in air.
