Answer:
They all hit at the same time
Explanation:
Let the time of flight is T.
The maximum height is H and the horizontal range is R.
The formula for the time of flight is
[tex]T=\frac{2uSin\theta }{g}[/tex] ..... (1)
Te formula for the maximum height is
[tex]H=\frac{u^{2}Sin^{2}\theta }{2g}[/tex] .... (2)
From equation (1) and (2), we get
[tex]\frac{T^{2}}{H}=\frac{\frac{4u^{2}Sin^{2}\theta }{g^{2}}}{\frac{u^{2}Sin^{2}\theta }{2g}}[/tex]
[tex]\frac{T^{2}}{H}=\frac{8}{g}[/tex]
[tex]T=\sqrt{\frac{8H}{g}}[/tex]
here, we observe that the time of flight depends on the maximum height and according to the question, the maximum height for all the three balls is same so the time of flight of all the three balls is also same.
