contestada

A football is kicked vertically upward from the ground and a student gazing out of the window sees it moving upward past her at velocity U. The window is a height h above the ground. You may ignore air resistance. How high does the football go above ground?

Respuesta :

Answer:

[tex]H = \frac{u^2}{2g} + h[/tex]

Explanation:

Let the football is kicked up vertically with some speed given as

[tex]v = v_o[/tex]

now its speed when it will reach to height "h" above the ground is given as "u"

so we will have

[tex]v_f^2 - v_i^2 = 2 a d[/tex]

here we have

[tex]u^2 - v_o^2 = 2(-g)h[/tex]

so we have

[tex]v_o^2 = u^2 + 2gh[/tex]

now we know that when football will reach to maximum height then it will have zero final velocity

So we will have

[tex]v_f^2 - v_i^2 = 2 a s[/tex]

[tex]0 - (u^2 + 2gh) = 2(-g)H[/tex]

so we have maximum height given as

[tex]H = \frac{u^2 + 2gh}{2g}[/tex]

[tex]H = \frac{u^2}{2g} + h[/tex]

Otras preguntas